F(-6)=x^2+10

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Solution for F(-6)=x^2+10 equation: 



(-6)=F^2+10

We move all terms to the left:

(-6)-(F^2+10)=0

We add all the numbers together, and all the variables

-(F^2+10)-6=0

We get rid of parentheses

-F^2-10-6=0

We add all the numbers together, and all the variables

-1F^2-16=0

a = -1; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·(-1)·(-16)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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